In his most famous paradox Zeno proves that anything that is
moving can never catch up with anything that is moving slower than
it.
The slower when running will never be overtaken by the quicker;
for that which is pursuing must first reach the point from which that
which is fleeing started, so that the slower must necessarily always
be some distance ahead.'
Let's look at what he says.
First assume that a hare is chasing a tortoise. The tortoise starts
some distance ahead - lets say 10 metres. They both start running at the
same time. The hare runs at a speed of 10 metres every second and the
tortoise runs at a speed of 1 metre every second. After 1 second the
hare has got to the tortoise's starting position, but the tortoise has
moved 1 metre in the same time, so the hare has not caught up yet. The
tortoise is now 1 metre ahead, but by the time the hare travels 1 metre
the tortoise has traveled 10cm. The tortoise is now 10 cm ahead, but by
the time the hare travels 10cm the tortoise has traveled 1cm. The
tortoise is now 1 cm ahead. I could keep going on indefinitely but you
should see that the tortoise is always a bit further on when the hare
gets to where he was.
Notes
Everybody knows in the real world Zeno's Statement is wrong. After
all, if it were true the world would be a very different
place. For one, the current hunting debate would not exist, as
there would be no hunting. No one would chase a fox if they could never
catch it. Although the statement is clearly not correct, Zeno's argument
baffled the Greek philosophers - as well as the philosophers that came
after them. Zeno's riddle plagued mathematicians for nearly two thousand
years.
The Solution
It is the infinite that lies at the heart of Zeno's Paradox. Zeno had
taken continuous motion and divided it into infinite steps. The Greeks believed
that because there were infinite steps the race would go on forever,
even though the steps got smaller and smaller. The ancient Greeks didn't
have the mathematical knowledge to deal with the infinite, but modern mathematics
does. The infinite must be approached very carefully, but it can be
mastered.
It is sometimes possible to add an infinite number of terms together
and get a finite result, but to do so the terms must approach zero.
(This is a necessary, but not a sufficient condition. If the terms go to
zero too slowly then the sum will not converge to a finite number).
Lets take another look at the problem. To make the numbers easier to
work with lets assume that the hare runs twice as fast as the tortoise
and that it starts 1 metre away. The logic still works. When the hare
has traveled 1 metre the tortoise will have traveled a ½ metre. When
the hare travels that ½ metre the tortoise will have traveled a ¼
metre further etc.
Let's look at the distances the hare runs in each step
|
Distance Traveled (m) |
| 1 |
1 |
| 1/2 |
0.5 |
| 1/4 |
0.25 |
| 1/8 |
0.125 |
| 1/16 |
0.0625 |
| 1/32 |
0.03125 |
| 1/64 |
0.015625 |
| 1/128 |
0.0078125 |
| 1/256 |
0.00390625 |
| 1/512 |
0.001953125 |
| 1/1024 |
0.0009765625 |
You can keep adding rows to this table and the number will not
reach 0, but it will get closer and closer. This is true until you add
an infinite number of rows. The distance then approaches:
Modern mathematicians say that the terms have a limit.
If after infinite steps the the step size is zero, the journey has a
destination. Once the journey has a destination it is easy to ask how
long it will take to get there. This is something the Greeks could not
do as they could not deal with infinity and therefore their race had no
destination.
Now lets add the distance the hare runs
|
Total distance traveled (m) |
| 1 |
1 |
| 1 + 1/2 |
1.5 |
| 1 + 3/4 |
1.75 |
| 1 + 7/8 |
1.875 |
| 1 + 15/16 |
1.9375 |
| 1 + 31/32 |
1.96875 |
| 1 + 63/64 |
1.984375 |
| 1 + 64/128 |
1.9921875 |
| 1 + 255/256 |
1.99609375 |
| 1 + 511/512 |
1.998046875 |
| 1 + 1023/1024 |
1.9990234375 |
The numbers 1+(1/2)+(1/4)+(1/8)+(1/16)+(1/32)+....+(1/2n)+...
approach 2 as the limit. In the same way that the steps the hare runs
get smaller and smaller, and closer and closer to zero the sum of these
steps get closer and closer to 2. How do we know this? Well, lets start
off with 2, and subtract the terms of the sum one by one. To start with
we take 2 and subtract 1, which is of course,1. next subtract 1/2,
leaving 1/2. Now take off 1/4, leaving 1/4, Next take off 1/8, leaving 1/8.
We can see we are back to the familiar sequence, and as we know
1,1/2,1/4,1/8 etc has a limit of zero subtracting these sums from 2 will
leave 0. So the hare will catch up the tortoise in 2 metres

Now if we go back to our original step sizes of 10,1,0.1,0.01,0.001
the terms again approach 0 and the sum of the terms approach 11.11111
(the .11 is recurring i.e. goes on for ever). So the hare will catch up
with the tortoise in 1 + 1/9 metres (0.111111 = 1/9). There exists the
possibility for some confusion here - you may believe that as the 1's go
on forever so does the race, but don't be fooled. 0.11111111 recurring
is a real number - it is 1/9 (Type 1 ÷ 9 into a calculator to
check this). although a metre is not exactly divisible by 1/9 (it is
11.1111111cm) this is only a man made problem. We have 100cm in a metre
simply because it is easy to work with, we can quite easily split the
metre into any number of sub units, as do other measurement standards
(the foot contains 12 inches for example). If we choose 90 sub units and
give them a name - lets call them nics, but any word will do. (we define
the nic as 1 ninetieth of a metre) We can now see that the hare will
catch up the tortoise in 11.111111 metres or exactly 11 metres
and 10 nics. (1 metre = 90 nics : (1/9)x90 = 10)
Now we know the distance we can also work out how long it will last.
Since the race is 11 and 1/9 of a metre in length, and the hare is
running at 10 metres per second (22.37mph - That's one fast hare) it is easy to work out that the hare
will catch the tortoise in 1 and 1/9 of a second. (see previous
paragraph regarding this 1/9 of a sec).
Footnote
The Greeks couldn't do this neat mathematical trick. They didn't have
the concept of the limit. They didn't believe in 0 and they couldn't
handle the infinite. This is the biggest failure in Greek mathematics,
and is the only thing that stopped them discovering calculus.
If you understand the reasoning behind the answer to this paradox you
are on the road to understanding calculus. And
you thought math's was hard!
Other Explanations
If you don't understand the above answer fully then consider
this.
The distance the hare travels in each step is 1/10 of the previous
step distance. If you believe that you can keep on dividing a number by
10 forever Zeno must be correct. But we know he is not correct so there
must be a problem somewhere. The mathematical world and the real world
don't agree, as we know the hare will catch the tortoise. Maybe the error
is our assumption that we can keep dividing a number by 10. We
must change this assumption and state that in the real world (unlike in
the mathematical world) space
cannot be divided into an infinite number of steps. If this is true there
is a smallest distance one can travel. Let's look at what this means. If
the distance between A and B is the smallest distance that can be
traveled and you were standing at A and moved to B you would never be
anywhere in between. This sounds almost as strange as our original statement
that a slower object could not be overtaken by a faster one, but Quantum
Mechanics (The study of the very small) seams to backup this idea. In
Quantum Mechanics there is a smallest distance you can travel. It a
distance around 1019 (10000000000000000000) times
smaller than a proton. Distance's this small are smaller than atoms by
as much as atoms are smaller than stars.
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